How to get the smallest difference(Array)

>>The issue i'm having is that if there are two values of equal difference only the closest one is displayed. Can someone please correct my coding.
function[smallestPosition] = FindSmallestElevationChange(i,B)
E = [ 3 6 5 4 7 8 3 ; 5 7 6 2 3 1 7 ; 6 8 5 8 5 4 8 ; 7 4 9 7 6 5 3 ];
*%B = 3 adjacent values e.g.. if I chose E(10), B = [ 4 2 8 ]
%the smallest difference should be 4 and 8 which is (1 and 3) respectively
%since there is a difference of 2 for both of them.*
E(i);
[c index] = min(abs(B-E(i)));
the output given is only 1(which is 4)
[REVERTED, was edited away by the OP, Jan]

7 Comments

Please not that....._min_ gives you only minimum value....so output is only one value. What you are expecting?
What's the point of uploading that picture? You expect us to read it this way?
Where on god's green earth is abs(10-8) equal to abs(10-4)?
Let me rephrase. Unless something very basic has changed, there is no way that
2 == 4
You probably meant E(6) (just dawned on me, I need coffee). If that's the case, my answer should solve your problem.
Well then I don't understand what you are trying to achieve.
Cedric
Cedric on 17 Sep 2017
Edited: Cedric on 17 Sep 2017
Shivam Prasad, the least you can do if you don't need help anymore, is to accept the answer of whoever was nice enough to give you freely part of his/her time.
I accepted the answer from José-Luis (before Jan restored the original question and answered).
The question was originally titled "How to get the smallest difference(Array)" and it had the following picture attached:
Jan
Jan on 17 Sep 2017
Edited: Jan on 17 Sep 2017
I have reverted the question. Please, Shivam Prasad, do not remove the question after somebody has spent the time to provide an answer.

Sign in to comment.

 Accepted Answer

bla = randi(50,10);
val = 25;
result = abs(bla-val);
result = result == min(result(:));
[xx,yy] = ndgrid(1:size(bla,1),1:size(bla,2));
idx_x = xx(result)
idx_y = yy(result)

More Answers (1)

Jan
Jan on 17 Sep 2017
Edited: Jan on 17 Sep 2017
The question does not contain the detail, that the input is a matrix, but a scalar and a vector only. Then:
[c, index] = min(abs(Vec - E));
is almost a solution. Do it in two steps:
Dist = abs(Vec - E);
and then use this to determine the indices:
Dist == min(Dist)

Categories

Products

Asked:

on 31 Aug 2017

Edited:

on 17 Sep 2017

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!