displaying image

i have a code

for j1 = 1:size(A1_20,3)

      for j = 1:J
      % loop thru subbands
      for s1 = 1:2
          for s2 = 1:3
              w{j}{s1}{s2} =A1_20(:,:,j1);
              y1 = idualtree2D(w, J, Fsf, sf);
              Er= mean2((single(x) - single(y1)).^2);
              final_col2{j1}=Er;

end
            end
    end
end

in this i have 20 images in y1 and for each i have found error,now i want to display image which has minimum error,please help

Answer 1

[Image Analyst]

I think you know the basic code for keeping track of the max or min where you set the global min to some huge number (say, inf)

globalMin = inf;

and then in the loop, get the value you want the min of, and do something like

if thisMin < globalMin
  % This (the current) min is less than our lowest min.
  % Save this min as our new global min and keep track of the index.
  % Keep track of j1, j, s1 and s2 if you need to.
  globalMin = thisMin;
  indexAtGlobalMin = loopIndex;
end

The code is similar if you want to find the max, just use -inf and ">" instead of "<". In your case, of course, thisMin is your "Er" variable, and you might call globalMin "lowestError" or something descriptive like that.

[kash]

can u please tell what is thismin and loopIndex please

[Image Analyst]

thisMin is your "Er" variable. The loopIndex is j1, j, s1 and s2 - whichever you want to keep track of.

[kash]

if Er < globalMin

% This (the current) min is less than our lowest min.

% Save this min as our new global min and keep track of the index.

% Keep track of j1, j, s1 and s2 if you need to.

globalMin = thisMin;

indexAtGlobalMin = j1;

end

i sthis correct ,then how to display image

Answer 2

[Thomas]

do you have your 20 error values in final_col2? assuming you do..

final_col2=rand(20,1)  % I have created random data for error
final_col2 =
          0.75
          0.26
          0.51
          0.70
          0.89
          0.96
          0.55
          0.14
          0.15
          0.26
          0.84
          0.25
          0.81
          0.24
          0.93
          0.35
          0.20
          0.25
          0.62
          0.47

>>q = min(final_col2)
q =
          0.14
>>p =find(final_col2==(min(final_col2)))
p =
          8.00

In the above example you will find that image 8 has the minimum error..

[kash]

In such cases i want to display the first image

[Thomas]

Do you mean as you are running through the loop you wan to display the image with the current lowest error?

[kash]

YES THOMAS

[Image Analyst]

Why couldn't you just keep track of which has the lowest error like I showed you how to do?

[Thomas]

Yes, Image Analyst's answer is the best one in this case... Just keep track of the minimum inside the loop.

@ image analyst: +1 for your answer