multiple area with different base values

Is it possible to show multiple area in a graph with different base values ? In the following example, the base value of the first area is changing when the second one is displayed.
figure
x = linspace(0,2*pi);
y = sin(x);
plot(x,y,'linewidth',2);
hold on;
f = y>=0.9;
h(1) = area(x(f),y(f),...
'BaseValue',0.9,...
'ShowBaseLine','off',...
'FaceColor','red',...
'FaceAlpha',0.2,...
'LineStyle','none');
fprintf('basevalue: %.2f\n',h(1).BaseValue);
f = y<=-0.3;
h(2) = area(x(f),y(f),...
'BaseValue',-0.3,...
'ShowBaseLine','off',...
'FaceColor','green',...
'FaceAlpha',0.2,...
'LineStyle','none');
fprintf('basevalue: %.2f\n',h(1).BaseValue);
Thanks for the help ! (Matlab R2016b)

1 Comment

One way to bypass this issue :
figure
x = linspace(0,2*pi);
y = sin(x);
plot(x,y,'linewidth',2);
hold on;
bv = 0.9;
f = y>=bv;
ybv = repmat(bv,1,sum(f));
h = area([x(f);x(f)]',[ybv;y(f)-ybv]',...
'ShowBaseLine','off',...
'FaceColor','red',...
'FaceAlpha',0.2,...
'LineStyle','none');
delete(h(1));
f = y<=-0.3;
h2 = area(x(f),y(f),...
'BaseValue',-0.3,...
'ShowBaseLine','off',...
'FaceColor','green',...
'FaceAlpha',0.2,...
'LineStyle','none');
but...

Sign in to comment.

Answers (2)

I compared the graphs generated from the above code snippets posted by you. The second code snippet seems to give the expected results. Any reason why this solution is not acceptable to you?

1 Comment

Indeed the second code snipped gives the expected results but is much less intuitive. Is is a bug or a feature to have only one BaseValue per axis ?

Sign in to comment.

I was facing a similar issue, solved it by using "Shade area between two curves" function by John Bockstege. The file exchange link for this function is below:
https://www.mathworks.com/matlabcentral/fileexchange/13188-shade-area-between-two-curves
It does not consider base value, but basically shades the area between two lines. So one line can be your vector and the other can be a baseline*ones(size(x)).
Hope this helps.
Regards, Ullekh

Categories

Asked:

on 17 May 2017

Answered:

on 16 Jun 2018

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!