Computational problem

Hi, this simple code gives a matrix.
n=6;
m=5;
for p=2:1:(n-1)
cc=(2+(m*(p-1))):1:(m*p-1)
end
in the command window it returns the values: 7,8,9,12,13,14,17,18,19,22,23,24; but in the workspace it save a matrix of three elements: 22,23,24. How could I do to have a matrix of all element? (if is possible without for) Regards

 Accepted Answer

n=6;
m=5;
p = 2:(n-1);
for j1 = numel(p):-1:1
cc(:,j1) = (2+(m*(p(j1)-1))):1:(m*p(j1)-1);
end
cc = cc(:).'

More Answers (0)

Categories

Find more on Linear Algebra in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!