Process file sets and store output in table rows

I have a total of 100 files. I need to calculate the mean of each column in every set of 5 files (1-5, 6-10, etc.) and store those values in arrays to display in a table. Currently, the code below calculates the mean of each column in the first 5 files, stores those values as an array, and displays them in one row of a table. However, I need help adding the arrays from files 6-10 etc. to the 2nd row etc. of the table. Any suggestions?

directory='/directory/files/';
files=dir([directory,'*.csv']);

means = [];
for i=1:5;
    data=csvread([directory,files(i).name],1,0);
    means=[means mean(data)]
end
array2table(means)

Answer 1

[Jan]

You can try something like this, which uses two counters to collect the data of 5 files and store them in a cell:

MeanC  = cell(1, numel(files) / 5);
iMeanC = 0;
aMean  = zeros(1, 5);
iMean  = 0;
for iFile = 1:numel(files)
    % [EDITED, Typo: i -> iFile]
    data = csvread(fullfile(directory, files(iFile).name), 1, 0);
    iMean        = iMean + 1;
    aMean(iMean) = mean(data, 1);  % Along 1st dimension
    if iMean == 5
      iMeanC        = iMeanC + 1;
      meanC{iMeanC} = aMean;
      iMean         = 0;
    end
end

% Care for last chunk if number of files is not a multiple of 5:
if iMean ~= 0
   iMeanC        = iMeanC + 1;
   meanC{iMeanC} = aMean;
end

[AG]

When I run the code provided in the answer, I get the following error:

Subscript indices must either be real positive integers or logicals.

data = csvread(fullfile(directory, files(i).name), 1, 0);

Any ideas how to correct this?

[Jan]

@AG: Thanks for finding this typo: i -> iFile . This is fixed now.

[AG]

Now I get this error:

In an assignment A(:) = B, the number of elements in A and B must be the same.

Error in program (line 13) aMean(iMean) = mean(data, 1); % Along 1st dimension