Finding intersection point of the lines
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Hi I have data sets for two lines. i.e. x1,y1 and x2,y2. So i can plot the lines using these point data sets. I would like to know the point (x,y)where these lines intersect each other. Please note that i have tried both [x,y]=intersections(x1,y1,x2,y2); and [x,y]=curveintersect(x1,y1,x2,y2);
i would appreciate if you can tell me the exact command for this purpose.
Regards
1 Comment
Jorge Celedón
on 13 Dec 2018
Edited: madhan ravi
on 13 Dec 2018
Accepted Answer
More Answers (4)
Jorge Celedón
on 13 Dec 2018
Edited: madhan ravi
on 13 Dec 2018
1 vote
2 Comments
Nicholas Ayres
on 26 Jan 2022
Heads up to people who find this. This requires the Mapping Toolbox
Vladimir Jara
on 23 Sep 2022
thanks for the heds up!
Andrei Bobrov
on 5 Mar 2012
data = rand(20,3);
x1 = sort(data(:,2));
x2 = sort(data(:,3));
y = data(:,1);
pp = interp1(x1,y,'linear','pp');
pp2 = interp1(x2,y,'linear','pp');
xx = xx(max(x1(1),x2(1)) <= xx & min(x1(end),x2(end)) >= xx);
func = @(x)ppval(pp,x)-ppval(pp2,x);
xb = xx([true; diff(func(xx) > 0) ~= 0]);
i1 = hankel(1:2,2:numel(xb));
xout = arrayfun(@(z)fzero(func, xb(i1(:,z))), (1:size(i1,2))' )
1 Comment
Agnieszka Dybalska
on 6 Jan 2021
It returns - not known function xx...
mohammed wasiullah
on 5 Apr 2017
0 votes
how to find the intersection between the curve and the straight ?
1 Comment
Tan Kah Loon
on 18 Apr 2017
Example,y1=x^2+2x+3,y2=2x^2+3x+4 , you have to combine two eq and you get ((x^2+X+1)), type f=[1 1 1] to get the polynomials func and roots (f) for its roots.Next, you have to type your 1st equation into p=[1 2 3], after that, pvals=polyval (p,-0.5) and you will find the 1st intersection. The 2nd intersection use back the same method to find.
Preetham Manjunatha
on 8 Feb 2022
0 votes
Here is the link to find the intersection point of two line segments/lines. A fast two line intersection point finder based on the line parametric space. Finds the intersection point between two lines if it exists or else submits NaN.
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