Combine rows of 2 Matrices based on a columns cell value

I have two matrices. The first matrix "A" has 2 columns and 425 rows of data. Matrix "B" has 10 columns and 468 rows of data.

I need to assign rows 5 through 9 of Matrix B into rows 3 through 7 of Matrix A based on matching values in column 2 of B and column 10 in A (2 and 10 are indexes). For example:

Matrix A:
711875   1
711883  32
711884  22
712548  43

Matrix B:
1950  11  22  5  -1.5  46  -1.9  21  1  1
1951  3  11  5  -2.0  42  -1.6  33  1  2
1958  2  12  8  -2.0  34  -2.6  16  1  3
1960  2  29  17  -1.9  41  -2.2  25  1  4
1962  1  7  6  -1.6  34  -1.7  18  1  5
1962  12  8  6  -2.1  34  -2.1  16  1  6
1963  12  14  8  -1.6  37  -1.8  17  2  7
1965  3  3  6  -1.6  43      -1.5  31  2  8
1966  1  24  8  -1.6  35  -2.1  16      3  9
1967  2  21  5  -1.5  41  -2.1  22  3  10

The output should then be:

[711875,  1,  1950,  11,  22,  5,  -1.5,  46,  -1.9, 21,  1,  1]

where the " , " denotes columns. Therefore the first two columns would be from Matrix A while the last 10 columns would be from Matrix B. So 12 columns in total.

Answer 1

[per isakson]

Try the code below. (Note that I have modified the example somewhat. All values of A(:,2) should be members of B(:,10) ???)

A = [
711875   1
711883   4
711884   7
712548  10 ];

B = [ 
1950  11  22  5  -1.5  46  -1.9  21  1  1
1951  3  11  5  -2.0  42  -1.6  33  1  2
1958  2  12  8  -2.0  34  -2.6  16  1  3
1960  2  29  17  -1.9  41  -2.2  25  1  4
1962  1  7  6  -1.6  34  -1.7  18  1  5
1962  12  8  6  -2.1  34  -2.1  16  1  6
1963  12  14  8  -1.6  37  -1.8  17  2  7
1965  3  3  6  -1.6  43      -1.5    31  2  8
1966  1  24  8  -1.6  35  -2.1  16      3       9
1967  2  21  5  -1.5  41  -2.1  22  3      10 ];
C = cat( 2, A, B( A(:,2), : ) );
[~,ixb] = ismember( A(:,2), B(:,10) );
D = cat( 2, A, B( ixb, : ) );
all( C(:)==D(:) )

If neither C nor D is what you want, please review your question.

[Tyler Smith]

C is exactly what I need! Thanks so much!