Remove row in cell array depending on value of first column.

I would like to know how to remove each row on each cell in a cell array where the value of the first column is below 6.

I’ve got this cell array with hundreds of cells where each cell is a matrix of a different dimension. The fist 8 cells look like:

C =    {36x4 double}
       {5x18 double}
       {5x2 double}
       {13x9 double}
       {2x7 double}
       {20x2 double}
       {20x2 double}
       {9x7 double}

For example the third cell of C is {5x2 double} and is composed of:

1  5
19 10
5  4
6  6
21 9

So the end result for that cell should be:

19 10
6  6
21 9

Answer 1

[Matt J]

   result = cellfun(@(z) z(z(:,1)>=6,:)  , C ,'uni',0)

Answer 2

[Cedric]

The easiest way is using a loop:

 for cId = 1 : numel( C )
    isLt6 = C{cId}(:,1) < 6 ;
    C{cId} = C{cId}(~isLt6,:) ;    % Or C{cId}(isLt6,:) = [] ;
 end

Then you have more compact ways to do it, which may not be more efficient overall, e.g.:

 C = cellfun( @(c) c(c(:,1)>=6,:), C, 'UniformOutput', false ) ;

Answer 3

[the cyclist]

output = cellfun(@(x)x(x(:,1) >= 6,:),C,'UniformOutput',false)