How do I get a specific number of successive ones in my binary matrix?

I would like to create a binary 3D matrix (60x96x10), where there are 60*96 ones finally, and their position is randomized and unique. Everytime a 1 occurs, i would like 2 more ones to come after it, but my code is glitching and gives 4 or 5 ones everytime I run it. What is wrong with my code?

function cubefinal = sensingmatrix3d(time)
  exposure=zeros(60,96,10);
  if time==3
     for j=1:size(exposure,1);
      for jj=1:size(exposure,2);
          randnum=randi([1 8]);
          exposure(j,jj,randnum:randnum+2)=1;
      end
     end
  end
end

Answer 1

[the cyclist]

I ran the following test code (which fills in 1's exactly as yours does). It displays a few lines at random, and also checks that the total number of 1's is the expected value.

exposure = zeros(60,96,10);

for j=1:size(exposure,1);
for jj=1:size(exposure,2);
    randnum=randi([1 8]);
    exposure(j,jj,randnum:randnum+2)=1;
    % Randomly select some rows to spot-check 
    if rand < 0.003
        checkRow = reshape(exposure(j,jj,:),[1 10])
    end
end
end

% Confirm that there are the expected number of ones in the array
sum(exposure(:)) == 60*96*3

I'm not sure what you think is wrong, but the code does seem to do what you want it to.

[tash7827]

am i calling this function correctly?

Answer 2

[Azzi Abdelmalek]

exposure=zeros(60,96,10);
[n,m,p]=size(exposure)
[xx,yy]=ndgrid(1:n,1:m);
randnum=cell2mat(arrayfun(@(x) x:x+2,randi([1 8],1,60*96),'un',0));
xx=repmat(xx(:)',3,1)
yy=repmat(yy(:)',3,1)
idx=sub2ind([n,m,p],xx(:),yy(:),randnum');
exposure(idx)=1