how i can find index of each element

hello all; i have one problem which

Ex_BWLasColum=[14;20;2;16;1;1;8;1;1;1;1;6;1;1;17;2;24;2;25;8;9;1;1;1;1;1;3;1;1;1;1;1;1;1;1;1];
Ex_BWFirscolm=[1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;1;2;2;2;3;6;8;8;9;14;16;17;20;24;25];
how i can find index of each element of Ex_BWFirscolm from Ex_BWLasColum.

Answer 1

[Andrei Bobrov]

Only in your case:

[~,ii] = sort(Ex_BWLasColum);

[Thorsten]

i.e., in the case where Ex_BWLasColum contains no elements that are not contained in Ex_BWFirscolm.

[Andrei Bobrov]

yes

Answer 2

[the cyclist]

[tf,loc] = ismember(Ex_BWFirscolm, Ex_BWLasColum);

(Or maybe switch the input arguments. I'm not sure which way you meant.)

tf is a boolean that indicates whether the element is present, and loc is an index that tells you the location. It sounds like you want loc.

[Mohamuud hassan]

thank you the cyclist; the output:

         5
         5
         5
         5
         5
         5
         5
         5
         5
         5
         5
         5
         5
         5
         5
         5
         5
         5
         5
         5
         5
         5
         3
         3
         3
        27
        12
         7
         7
        21
         1
         4
        15
         2
        17
        19
the first 22 elements was solved according to the element 1 of  Ex_BWLasColum so, that was not my point.
my objective is to find first similar element of Ex_BWFirscolm according to similar number in the Ex_BWLasColum. then the second element of Ex_BWFirscolm according to the second similar number in the Ex_BWFirscolm. N.B:
the estimated result is: 5,6,8,9,10,11,........