How can I find the set of vertices of hexagons which are adjacent to a random point?
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    Aravind Varma Dantuluri
 on 10 Aug 2024
  
    
    
    
    
    Commented: Aravind Varma Dantuluri
 on 13 Aug 2024
            I have a set of hexagons whose blue coordinates are known:

I have a random red point and I need to know the 4 (in some cases it would be 3) points which are immediately adjacent to it. These points are contained in the black box shown for illustration.
I tried to sort the blue points by measuring distances but I keep getting extra points (shown by black arrows) or missing the required points.
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Accepted Answer
  Matt J
      
      
 on 13 Aug 2024
        
      Edited: Matt J
      
      
 on 13 Aug 2024
  
      hex=[         0   -1.0000
   -0.8660   -0.5000
   -0.8660    0.5000
         0    1.0000
    0.8660    0.5000
    0.8660   -0.5000
    1.7321   -1.0000
    0.8660   -0.5000
    0.8660    0.5000
    1.7321    1.0000
    2.5981    0.5000
    2.5981   -0.5000
    3.4641   -1.0000
    2.5981   -0.5000
    2.5981    0.5000
    3.4641    1.0000
    4.3301    0.5000
    4.3301   -0.5000]  %hexagon points
hex=unique(hex,'rows');
given=[1.2,-1];
pts=[given;hex];
DT=delaunayTriangulation(pts);
CL=DT.ConnectivityList;
idx=any(CL==1,2);
idx=setdiff(CL(idx,:),1);
nearest=pts(idx,:)
plot(hex(:,1),hex(:,2),'x', nearest(:,1),nearest(:,2),'o',given(:,1),given(:,2),'s'); 
legend Vertices Nearest Given
axis equal padded
More Answers (1)
  Mario Malic
      
 on 10 Aug 2024
        Hi,
here's some code to give you an idea
X = rand(3,3);
Y = rand(3,3);
pts = [X(:), Y(:)];
distance = squareform(pdist(pts)); % symmetric matrix that contains distances between points
% distance between pt3 and all other pts
[~, idx] = sort(distance(:, 3));
closestPts = idx(2:5) % first one is distance between pt3 and pt3 so we ignore that
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