How to assign pair of values to a single aeeay in the matrix using two different vectors

fsine=50e6:0.4e9:3e9;
Vp=0:0.5:3;
I need to form a matrix such that columns correspons to different Vp for a single fsine.
the first column should be for fsine=50e6 for all values for Vp and second column should be fsine=50e6+0.1e9 for all values in Vp
The final vector should be have 7 rows and 8 columns.

Answers (2)

Hi Yogesh
The following code might help you:
fsine=50e6:0.4e9:3e9
fsine = 1x8
1.0e+09 * 0.0500 0.4500 0.8500 1.2500 1.6500 2.0500 2.4500 2.8500
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Vp=0:0.5:3
Vp = 1x7
0 0.5000 1.0000 1.5000 2.0000 2.5000 3.0000
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M=zeros(7,8);
for idx1=1:7
for idx2=1:8
M(idx1,idx2)=sin(fsine(idx2)*Vp(idx1));
end
end
M
M = 7x8
0 0 0 0 0 0 0 0 -0.4668 0.9423 -0.9201 0.4119 0.3139 -0.8739 0.9723 -0.5571 0.8256 0.6309 -0.7208 -0.7507 0.5960 0.8497 -0.4548 -0.9253 -0.9935 -0.5200 0.3554 0.9562 0.8179 0.0476 -0.7595 -0.9797 0.9316 -0.9790 0.9992 -0.9919 0.9572 -0.8960 0.8101 -0.7018 -0.6543 -0.1354 0.4274 0.8516 0.9997 0.8237 0.3806 -0.1859 0.2256 0.8883 -0.6644 -0.5600 0.9411 0.0951 -0.9881 0.3931
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1 Comment

fsine = 50e6:.4e9:3e9;
Vp = 0:.5:3;
M=sin(Vp.'*fsine)
M = 7x8
0 0 0 0 0 0 0 0 -0.4668 0.9423 -0.9201 0.4119 0.3139 -0.8739 0.9723 -0.5571 0.8256 0.6309 -0.7208 -0.7507 0.5960 0.8497 -0.4548 -0.9253 -0.9935 -0.5200 0.3554 0.9562 0.8179 0.0476 -0.7595 -0.9797 0.9316 -0.9790 0.9992 -0.9919 0.9572 -0.8960 0.8101 -0.7018 -0.6543 -0.1354 0.4274 0.8516 0.9997 0.8237 0.3806 -0.1859 0.2256 0.8883 -0.6644 -0.5600 0.9411 0.0951 -0.9881 0.3931
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fsine=50e6:0.4e9:3e9;
Vp=0:0.5:3;
result = repmat(Vp(:),1,numel(fsine))
result = 7x8
0 0 0 0 0 0 0 0 0.5000 0.5000 0.5000 0.5000 0.5000 0.5000 0.5000 0.5000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.5000 1.5000 1.5000 1.5000 1.5000 1.5000 1.5000 1.5000 2.0000 2.0000 2.0000 2.0000 2.0000 2.0000 2.0000 2.0000 2.5000 2.5000 2.5000 2.5000 2.5000 2.5000 2.5000 2.5000 3.0000 3.0000 3.0000 3.0000 3.0000 3.0000 3.0000 3.0000
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Asked:

on 30 Jun 2024

Edited:

on 30 Jun 2024

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