Mean of cell array with non-uniform cell array size size

Hi,

I have a cell array that stores a vector in each cell. The vector in each cell usually has 5 elements but somtimes it does have more or less than 5 elements.

I want to take the mean per vector row for each cell row but only do this where the vector length is 5. I dont want to use the vectors that have more or less than 5 elements.

Thanks.

This is how far I got:

slots = 16;

for i=1:slots
    mean_height{i} = mean([heights{i,1:profiles(i)}],2)
end

Answer 1

[Florian Bidaud]

Something like this should do the job:

slots = 16;
height_row = [];
for i=1:slots
    for j = 1:profiles(i)
        if length(heights{i,j})==5
            height_row = [height_row heights{i,j}'];
        end
    end
    mean_height{i} = mean(height_row,2);
end

I don't really like the double loop, there might be something to do with logical indexing but I can't find my way around it.

Update:

Do this instead :

slots = 16;
for i=1:slots
    height_row = heights(i,1:profiles(i));
    height_row = height_row(cellfun('length',height_row)==5);
    mean_height{i} = mean([height_row{:}],2);
end

though I feel like you want to have the following in the end instead (depending on what you want to do):

mean_height{i} = mean(mean([height_row{:}]))

[Konvictus177]

This is exactly what I want. Thank you very much!

slots = 16;
for i=1:slots
    height_row = heights(i,1:profiles(i));
    height_row = height_row(cellfun('length',height_row)==5);
    mean_height{i} = mean([height_row{:}],2);
end