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Cut region of interest images from 3D stack with known indices and without for loop

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Hi! I am having trouble cutting region of interest from a 3D stack.
A small example, I have a 3x3x2 array of:
array = [1,2,3;4,5,6;7,8,9];
array(:,:,2) = [1,2,3;4,5,6;7,8,9];
mini image indices:
left = [1,2]
right = [2,3]
top = [1,2]
bottom = [2,3]
create mini images:
miniImages = array(top:bottom,left:right,:)
result:
miniImages(:,:,1) = [1,2;4,5]
miniImages(:,:,2) = [1,2;4,5]
However, I want the result to be:
miniImages(:,:,1) = [1,2;4,5]
miniImages(:,:,2) = [5,6;8,9]
It seems that it only uses the first indices in variables left, right, top, bottom to create all mini images.
Anyone know how to solve this? Currently I use a for loop over the indices, but I want to make it faster.
Thanks!

Accepted Answer

Matt J
Matt J on 2 Mar 2023
Edited: Matt J on 2 Mar 2023
I doubt anything will be faster than a loop, but you can try this:
array = [1,2,3;4,5,6;7,8,9];
array(:,:,2) = [1,2,3;4,5,6;7,8,9]
array =
array(:,:,1) = 1 2 3 4 5 6 7 8 9 array(:,:,2) = 1 2 3 4 5 6 7 8 9
left = [1,2];
top = [1,2];
bottom = [2,3];
right = [2,3];
args=cellfun(@(z)reshape(z,1,1,[]) , {left,top,bottom,right} ,'un' ,0);
[L,T,B,R]=deal(args{:});
[m,n,p]=size(array);
[I,J]=ndgrid(1:m,1:n);
lidx=T<=I & I<=B & L<=J & J<=R;
miniImages=reshape( array(lidx) ,B(1)-T(1)+1,R(1)-L(1)+1,[])
miniImages =
miniImages(:,:,1) = 1 2 4 5 miniImages(:,:,2) = 5 6 8 9
  1 Comment
Kevin Jansen
Kevin Jansen on 2 Mar 2023
Hey, awesome it worked! Much more difficult than I thought it would be. My code with larger arrays ran 380x faster without the for loop. Thank you so much!

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