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Hello, how can I do a (loop) for this equation to find more than one value of the CF ? Specifically, I mean more than one value for (xm)
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function [CF]= Coherence_Factor(xm,N);
CF = ((abs (sum(xm))).^2) / (N* sum(abs(xm.^2)))
end
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VBBV
on 31 Dec 2022
Edited: VBBV
on 31 Dec 2022
xm = rand(5,10);
N = 10;
[CF]= Coherence_Factor(xm,N)
function [CF]= Coherence_Factor(xm,N);
CF = ((abs (sum(xm))).^2) ./ (N* sum(abs(xm.^2)));
end
2 Comments
VBBV
on 31 Dec 2022
for loop is not needed to find more than one value of CF or xm. However, you can still get such result with for loop also as
xm = randi([0 10],1,10);
N = 10;
for k = 1:length(xm)
CF(k)= Coherence_Factor(xm(k),N);
end
plot(CF)
function [CF]= Coherence_Factor(xm,N);
CF = ((abs (sum(xm))).^2) / (N* sum(abs(xm.^2)));
end
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