I wanna define function which has flexible number of argument.

Hello and happy new year!

Now I'm considering to define function which has flexible arguments.

For example, let's have function F which full argument number is 3 such as F(a,b,c)

If b is 0, user don't need to assign c thus F(a,b) is enough. Otherwise full argument assignment is required.

Can I make this kind of flexible function?

Answer 1

[Shoaibur Rahman]

function out = F(varargin)
 % do stuffs
 % y = varargin{1}+varargin{2}
 % out = y+1; etc.

For flexible number of outputs:

function varargout = F(varargin)
% do stuffs
% varargout{1} = varargin{1}-varargin{2}
% etc.

[Dong-Gyu Jang]

Are u sure this is right? I defined similar function but got only error message telling me that number of argument is larger than what it should be.

[Shoaibur Rahman]

This should work in this way. Anyway, it would be better to see the part of your code and the errors generated by the code.

[Dong-Gyu Jang]

Oh, you're right. I've just not known varargin and used arbitary variable name. As the result, it was not operated! Thanks to your advice! my function is now upgraded:)