How to find the position of a specific characters containing in a string in a cell array
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hello. i have a 136x39 cell array like this one
'Data Name' 'Timestamp' 360 370
'001-Day 1-RE-1' '24/07/2014 10:17:10' -738.803345332164 -734.184486898226
'001-Day 1-RW-1' '24/07/2014 10:17:37' -707.272295650121 -703.634423319119
'001-Day 1-LE-1' '24/07/2014 10:19:20' -744.635983922777 -740.346463517543
'001-Day 1-LW-1' '24/07/2014 10:19:39' -751.552763303339 -747.041101104821
and I want to find the positions of 'RE','RW','LE','LW'. I tried with the function [RW1, RW2]=find(strcmp('RW', array)); but got no results. I also tried [RW1, RW2]=find(strcmp('*RW*', Acdelta)); or strfind..
Any ideas?
Many thanks
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Accepted Answer
Guillaume
on 22 Oct 2014
Use either strfind four times, once for each pattern (RE, RW, LE, LW). Note that strfind (and strcmp) does not accept wildcards, or regexp
pos = regexp(array(:, 1), 'RE|RW|LE|LW', 'once');
Note that you can't pass the full cell array to strfind or regexp, since it contains elements that are not strings. Here, I just pass the first column.
Also, in your example, the position is always the same, so why do you want to find it?
4 Comments
Guillaume
on 22 Oct 2014
Ok, I'm still not very clear on what you're trying to do and whether or not your question is actually answered.
If you want the position and the value that follows the 'RE/RW/LE/LW', you can use a different regular expression:
[pos, valuestr] = regexp(array(:, 1), '(?:RE|RW|LE|LW)-(\d+)', 'start', 'tokens', 'once');
values = cellfun(@(v) str2double(v), valuestr, 'UniformOutput', false);
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