Need help With "If" statement
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Hi everyone,
I have an if statement that looks like the following:
if ( n == 0 && m == 0 )
values = 1;
elseif ( n < 0 || m < 0 )
display('no')
elseif ( n == 1 && m == 1 )
w11 = sqrt(3);
values = w11*sqrt((1-cos(theta).^2))*pnmnew(m-1,m-1,theta,norm);
elseif (n == m )
wmm = sqrt((2*m+1)/(2*m));
values = wmm.*(1-cos(theta).^2).^(1/2).*pnmnew(m-1,m-1,theta,norm);
wnm = sqrt(abs(((2*n+1)*(2*n-1))/((n+m)*(n-m))));
wnmB = sqrt(abs(((2*(n-1)+1)*(2*(n-1)-1))/(((n-1)+m)*((n-1)-m))));
values = wnm*(cos(
elseif ( n ~= m )theta).*pnmnew(n-1,m,theta,norm)-(wnmB)^(-1)*pnmnew(n-2,m,theta,norm));
I was wondering how I could go from displaying "no" in the elseif statement to terminating it. I don't want it to recursion through values < 0. How would I make it so it ends when it hits that condition?
Thanks!
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More Answers (2)
Matt Fig
on 18 Feb 2011
I don't know what you mean by "I don't want it to recursion through values <0."
An IF statement is not a recursive thing. If you mean you want the function evaluation to stop where the DISP statement is, put a call to RETURN there.
2 Comments
Matt Fig
on 18 Feb 2011
In that case I would try to post the whole code, if it is not too long, and ask for help.
Matt Tearle
on 18 Feb 2011
Do you want that to be an error condition? In which case error('no') (in place of disp) will display the message and terminate execution.
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