Help on Disappearing Popupmenu

So I've created a GUI with a popupmenu, but it seems that whenever I try to populate the menu, it disappears, anyone know what going on. Thanks in advance. Heres an example of what I am trying to do.

var1 = {'Ex1','Ex2','Ex3'}
for i =1:length(var1)
  set(handles.popupmenu1,'String',var1(i),'Value',i)
end

Answer 1

[Image Analyst]

That code you gave will give you a single item (the last one) in the popup. Do not use a for loop. The items in a popup or listbox are not entered in one at a time like you tried, they are done all at once with a single call to set the string property. What you did was to set the entire list to just a single item, and you did it 3 times (once on each iteration of your for loop). Since there is only one item in there, and the value is now 3 (which is more than 1), the popup will not display.

To fix, send in all the items in one shot, then set the value.

var1 = {'Ex1', 'Ex2', 'Ex3'}
set(handles.popupmenu1, 'String', var1); % Send in all 3 items at once.
set(handles.popupmenu1, 'Value', length(var1)); % Set what item is selected (the last one).

[Franco]

That did it. Thanks buddy. Ive literally been working on this problem since last thursday. Thanks again!

Answer 2

[Azzi Abdelmalek]

Why the for loop?

var1 = {'Ex1','Ex2','Ex3'}
i=1
set(handles.popupmenu1,'String',var1,'Value',i)

[Franco]

because I need to change the position of the string in the menu, otherwise the value wi;l; always be 1 and I will get an error. I read online that this is why the popupmenu is disappearing, problem is that even though I set the value, its still disappearing and I can't understand why. Ive done it with set(handles.popupomenu1,'String',var1), but I still get the same error, so I thought that by looping through and setting the value incrementally, this would solve my issue; it hasn't.

(Warning: popupmenu control requires that Value be an integer within String range Control will not be rendered until all of its parameter values are valid )

[Azzi Abdelmalek]

There is something in your code that causes this problem, but not the lines of code you've posted

[Franco]

Ive checked and debug everything. var 1 is being set, the value is being changed, but its not doing the trick. I would post the code, but its too extensive.

[Image Analyst]

Azzi's code is correct. If it doesn't work, then do it in two separate steps, set the string first, and then the value. Do not use a for loop. The items are not entered in one at a time like you tried, they are done all at once with a single call to set the string property.