Indexing way to look for specifc cell arrays in a cell array of cell arrays?
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Hi! I have a cell array of "ordered-pair" cell arrays of strings, e.g.,
A = { {'aa','bb'}, {'cc','dd'}, {'ee','ff'} };
I'd like an indexing (i.e., not-explicitly-looping) way to return the "outer-most" indices of a single matching ordered-pair, e.g., if
X = {'cc', 'dd'};
then
whereEqual(X,A)
should return
[0 1 0].
Similarly, is there a not-explicitly-looping way to "flatten" A:
flatten(A) => {'aa', 'bb', 'cc', 'dd', 'ee', 'ff'}
Thanks for your help!
6 Comments
Fangjun Jiang
on 17 Aug 2011
You'd better provide an example to make your question effective.
Oleg Komarov
on 24 Aug 2011
http://www.mathworks.com/matlabcentral/answers/6200-tutorial-how-to-ask-a-question-on-answers-and-get-a-fast-answer
David Goldsmith
on 24 Aug 2011
Jan
on 25 Aug 2011
Both problems are in the wish-list already: The message vanishs under some circumstances and there is no notification for comments, just for answers. So you have look for new comments manually. This is not very convenient, but not terrible also: We have to _write_ the comments manually also.
David Goldsmith
on 25 Aug 2011
Jan
on 25 Aug 2011
The two problems already included in the wish-list: 1. The message disappears under some strange circumstances (something with empty lines, editing etc). 2. No notification for new comments.
Answers (3)
Jan
on 25 Aug 2011
A = { {'aa', 'bb'}, {'xx', 'yy'} };
B = { {'aa', 'bb'}, {'cc', 'dd'} };
function R = isMemberC(A, B)
R = false(size(A));
for i = 1:numel(A)
for j = 1:numel(B)
if isequal(A{i}, B{j})
R(i) = true;
break;
end
end
end
And according to your other thread: If a case-insensitive comparison is wanted, change the "if isequal..." line to:
function R = isMemberC(A, B)
R = false(size(A));
for i = 1:numel(A)
sizeA = size(A);
for j = 1:numel(B)
if isequal(sizeA, size(B{j}) && all(strcmpi(A{i}, B[j}))
R(i) = true;
break;
end
end
end
4 Comments
David Goldsmith
on 25 Aug 2011
David Goldsmith
on 25 Aug 2011
Fangjun Jiang
on 25 Aug 2011
Yes. Why so obsessed with no-loopers? My hair straights up whenever I saw cellfun with anonymous function.
Jan
on 25 Aug 2011
@David: Sometimes the most primitive implementation needs the fewest resources. An important rule is coming from the field of house economics: Never touch an item twice. In the original field, this means, that I put the dishes in the right place, if I hold them in my hands. For the programming it means, that it is efficient to reduce the number of accesses to the data. ISMEMBER involves two sortings and sorting means excessive data access. CELLFUN is a C-Mex function, which has to call MATLAB to perform the evaluation of the function handle for each cell element. And the needed mexCellMATLAB function has a lot of overhead. Therefore the CELLFUN(@isempty) is so much slower than CELLFUN('isempty'), which checks the dimensions inside the Mex function.
I'm using a lot of faster replacements for built-in MATLAB functions. You can look in my FEX submissions for some examples.
Fangjun Jiang
on 25 Aug 2011
You probably need to do it using for-loops.
A = { {'aa', 'bb'}, {'xx', 'yy'} };
B = { {'aa', 'bb'}, {'cc', 'dd'} };
Index=false(size(A));
for k=1:length(A)
for j=1:length(B)
if isequal(A{k},B{j})
Index(k)=true;
break;
end
end
end
2 Comments
Jan
on 25 Aug 2011
I have a deja-vu.
Fangjun Jiang
on 25 Aug 2011
I thought your keyboard latency was back. Apparently not!
Andrei Bobrov
on 25 Aug 2011
R = all(reshape(ismember([A{:}],[B{:}]),[],numel(A)))
OR
R = all(reshape(strcmp([A{:}],[B{:}]),[],numel(A)))
ADD
c = mat2cell(cellfun(@(x)[x{:}],[B';A'],'un',0),[numel(B);numel(A)],1)
R = ismember(c{:})';
4 Comments
Jan
on 25 Aug 2011
I'm not sure, if the elements of A and B have the same number of elements. In addition your method replies TRUE for {{'aa', 'bb'}} and {{'bb','aa'}}. Anotehr result, which is most likely not intented:
A = {{'aa', 'bb'}, {'xx', 'yy'}};
B = {{'aa', 'bb', 'cc', 'dd'}};
==> R = [1, 0], but I'd expect [0,0].
The OP's example is not enough to defined the problem exactly.
@David: Please insert the necessary details to define a unique result.
Andrei Bobrov
on 25 Aug 2011
Hi Jan! You're right, it is obvious.
I gave the answer for the particular case.
David Goldsmith
on 25 Aug 2011
Andrei Bobrov
on 26 Aug 2011
mat2cell(cellfun(@(x)[x{:}],[B';A'],'un',0),[numel(B);numel(A)],1)
ismember(ans{:})
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