How to sum specific value in 1:m ?

• m=1:2
• b(m)=sum(sin(1:m)*b)
• then the result
• b(1)=sin(b)
• b(2)=sin(b)+sin(2*b)
• But I need
• b(1)=sin(b)
• b(2)=sin(b)+sin(3*b)

for n

• b(n)=sin(b)+sin(3*b)+sin(5*b)+sin(7*b)...

[Azzi Abdelmalek]

b(1)=sin(b)

what the variable b (in the left and the right expression) represent?

[Mech]

• thank bro.
• I have just find solution

for m=1:5
f(m)=2*m-1
b(m)=sum(sin(f)*b)
end

Answer 1

[Mech]

for m=1:n
f(m)=2*m-1
b(m)=sum(sin(f)*b)
end