How to spread out an array of integers according to it's value?

Hi there, say I observe a random array of integers 1-10. x = [6 3 9 4 7 10]. how can i transform this array so each integer is stored in its integer-row value. so 6 would be stored in the 6th row, 3 in the 3rd row, 9 in the 9th row, and so on and the gaps(spaces where there is no integer would be just zero) like so: resultant X = [0 0 3 4 0 6 7 0 9 10]. any help would be appreciated.

thank you.

Answer 1

[Star Strider]

This works:

x = [6 3 9 4 7 10];
y = zeros(1,max(x));
y(x) = x

producing:

y =

     0     0     3     4     0     6     7    0     9    10