Integration of velocity not working, creating zeros

%%Calculation of Velocity and Acceleration
v(i,1)= trapz(jh(i,1));
a(i,1)= trapz(v(i,1));
This is what I am using for differentiation. But both of these are coming out in the workspaces as zero... I don't know what this is. jh is jump height, there are numbers for this

 Accepted Answer

trapz is an trapezoidal INTEGRATION routine, not differentiation
doc trapz
doc diff

2 Comments

sorry i did mean integration and it is not working
dpb
dpb on 15 May 2014
Edited: dpb on 16 May 2014
"not working" is NEVER sufficient explanation for a problem.
But, if v is velocity and a acceleration, then you're going the wrong way physically.
a=dv/dt --> v=Int(a dt)
As for the zero result, looks like jh(i,1) is a single point so there's nothing to integrate over (even though you need to be differentiating instead it would appear).

Sign in to comment.

More Answers (0)

Tags

Asked:

on 15 May 2014

Edited:

dpb
on 16 May 2014

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!