Hi community, I am ploting a figure and i want to center the figure in the plot

5 Apr 2014
2 Answers
Answer Accepted
Updated 5 Apr 2014
10 Views (30 days)

0 votes

When i plot my figure it apears like a little dot with gigantic scales, I want that when the plot opens up, it opens exactly where the figure is. Here is the example:
plot(d(:,1),d(:,2),'.')
d = 1.0e+03 *
0.0010 0
0.0010 -0.0000
0.0010 -0.0000
0.0010 -0.0000
0.0010 -0.0000
0.0010 -0.0000
0.0010 -0.0000
0.0010 -0.0000
0.0010 -0.0000
0.0010 -0.0000
0.0010 -0.0000
0.0010 -0.0000
0.0010 -0.0000
0.0010 -0.0000
0.0010 -0.0000
0.0010 -0.0000
0.0010 -0.0000
0.0010 -0.0000
0.0009 -0.0000
0.0009 -0.0000
0.0009 -0.0000
0.0009 -0.0000
0.0009 -0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0007 0.0000
0.0007 -0.0000
0.0007 -0.0000
0.0007 -0.0000
0.0007 -0.0000
0.0007 -0.0000
0.0007 -0.0000
0.0007 -0.0000
0.0007 -0.0000
0.0006 -0.0000
0.0006 -0.0000
0.0006 -0.0000
0.0006 -0.0000
0.0006 -0.0000
0.0006 -0.0000
0.0006 -0.0000
0.0006 -0.0000
0.0005 -0.0000
0.0005 -0.0000
0.0005 -0.0000
0.0005 -0.0000
0.0005 -0.0000
0.0005 -0.0000
0.0005 -0.0000
0.0005 -0.0000
0.0004 -0.0000
0.0004 -0.0000
0.0004 -0.0000
0.0004 -0.0000
0.0004 -0.0000
0.0004 -0.0000
0.0004 -0.0000
0.0004 -0.0000
0.0003 -0.0000
0.0003 -0.0000
0.0003 -0.0000
0.0003 -0.0000
0.0003 -0.0000
0.0003 -0.0000
0.0003 -0.0000
0.0003 -0.0000
0.0003 -0.0000
0.0002 -0.0000
0.0002 -0.0000
0.0002 -0.0000
0.0002 -0.0000
0.0002 -0.0000
0.0002 -0.0000
0.0002 -0.0000
0.0002 -0.0000
0.0002 -0.0000
0.0002 -0.0000
0.0001 -0.0000
0.0001 -0.0000
0.0001 -0.0000
0.0001 -0.0000
0.0001 -0.0000
0.0001 -0.0000
0.0001 -0.0000
0.0001 -0.0000
0.0001 -0.0000
0.0001 -0.0000
0.0001 -0.0000
0.0001 -0.0000
0.0001 -0.0000
0.0001 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0.0000 -0.0000
0 0
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0000 0.0000
0.0001 0.0000
0.0001 0.0000
0.0001 0.0000
0.0001 0.0000
0.0001 0.0000
0.0001 0.0000
0.0001 0.0000
0.0001 0.0000
0.0001 0.0000
0.0001 0.0000
0.0001 0.0000
0.0001 0.0000
0.0001 0.0000
0.0002 0.0000
0.0002 0.0000
0.0002 0.0000
0.0002 0.0000
0.0002 0.0000
0.0002 0.0000
0.0002 0.0000
0.0002 0.0000
0.0002 0.0000
0.0002 0.0000
0.0003 0.0000
0.0003 0.0000
0.0003 0.0000
0.0003 0.0000
0.0003 0.0000
0.0003 0.0000
0.0003 0.0000
0.0003 0.0000
0.0003 0.0000
0.0004 0.0000
0.0004 0.0000
0.0004 0.0000
0.0004 0.0000
0.0004 0.0000
0.0004 0.0000
0.0004 0.0000
0.0004 0.0000
0.0005 0.0000
0.0005 0.0000
0.0005 0.0000
0.0005 0.0000
0.0005 0.0000
0.0005 0.0000
0.0005 0.0000
0.0005 0.0000
0.0006 0.0000
0.0006 0.0000
0.0006 0.0000
0.0006 0.0000
0.0006 0.0000
0.0006 0.0000
0.0006 0.0000
0.0006 0.0000
0.0007 0.0000
0.0007 0.0000
0.0007 0.0000
0.0007 0.0000
0.0007 0.0000
0.0007 0.0000
0.0007 0.0000
0.0007 0.0000
0.0007 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0008 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0009 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0.0000
0.0010 0
9.9619 0.8716

Sign in to answer this question.

 Accepted Answer

Image Analyst
Image Analyst on 5 Apr 2014

0 votes

What's up with the last value? It's like 10,000 times as big as any of the other values. So all your values are crammed into a microscopic area near the origin because it has to expand the axes to be able to show your last value of d. Are you sure that's how you want to do it? If that value is not there, it does plot stuff you can see.

More Answers (1)

Azzi Abdelmalek
Azzi Abdelmalek on 5 Apr 2014
Edited: Azzi Abdelmalek on 5 Apr 2014

0 votes

Just use
plot(d(:,1),d(:,2))

4 Comments
Show 2 older comments Hide 2 older comments

Azzi Abdelmalek
Azzi Abdelmalek on 5 Apr 2014
Edited: Azzi Abdelmalek on 5 Apr 2014
What is the last point in your data?
This plot make more sens
plot(d(1:end-1,1),d(1:end-1,2),'.')
Jacob
Jacob on 5 Apr 2014
Its a function that outputs x & z, i put them together in d=[x,z]
To get this data copy the function and plug in:
airf='2415' (its a character ''); N=250; AoA=alphadeg*pi/180;
function [x,z]=panelgen(airf,N,AoA)
global x global z
if length(airf)==4 c=str2num(airf(1))/100; %read max camber p=str2num(airf(2))/10; %read position of max camber t=str2num(airf(3:4))/100; %read thickness to chord ratio else error('The airfoil descriptor should have 4 characters') end
x=zeros(N+2,1); z=x; for i=1:N+1 xt=1-0.5*(1-cos(2*pi*(i-1)/N)); %calculate panel endpoint x using cos distribution %calculate y ordinate for symmetric airfoil if i==1 i==N+1 yt=0; %ensure airfoil comes back to a point. else yt=5*t*(0.2969*sqrt(xt)-0.126*xt-0.3516*xt^2+0.2843*xt^3-0.1015*xt^4); end %calculate cambeline height and angle if (c>0) if xt<=p %if forward of max caber point theta=c*2*(p-xt)/p^2; yc=c*(2*p*xt-xt^2)/p^2; else %if aft of max camber point theta=c*2*(p-xt)/(1-p)^2; yc=c*((1-2*p)+2*p*xt-xt^2)/(1-p)^2; end else %if no camber theta=0; yc=0; end %apply camber and get final airfoil shape if i-1>=0.5*N x(i)=xt-yt*sin(theta); z(i)=yc+yt*cos(theta); else x(i)=xt+yt*sin(theta); z(i)=yc-yt*cos(theta); end end %add wake panel endpoint
x(N+2)=10000*cos(AoA);
z(N+2)=10000*sin(AoA);
Jacob
Jacob on 5 Apr 2014
Actually plot(d(1:end-1,1),d(1:end-1,2),'.') makes more sense! Thank you very much

Sign in to comment.

Categories

Find more on Airfoil tools in Help Center and File Exchange

Tags

Asked:

Jacob
Jacob
on 5 Apr 2014

Commented:

Jacob
Jacob
on 5 Apr 2014

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!