Why is there arguments of type double?

function linearinterp

x=linspace(-5, 2*pi, 30);

y=exp((-x./2).*sin(x.^2+8));

%Error in linearinterp (line 4) %points=refine(0, 7, 0.1);

points = refine(0, 7, 0.1);

plot(x, y, points, f(points), 'r+');

hold on

plot(points, f(points));

hold off

end

function points = refine(x1, x2, tol)

xm = (x1+x2)/2;

%Error in linearinterp>refine (line 12) %if abs((f(x1)+f(x2))/2-f(xm))<tol

if abs((f(x1)+f(x2))/2-f(xm))<tol

points=[x1,x2];

else

left=refine(x1, xm, tol);

right=refine(xm, x2, tol);

points=[left, right(2:length(right))];

end end

Answer 1

[Image Analyst]

Well, what is f? Is it somehow supposed to magically know what f is?

[Ehi Eromosele]

f is the y function.

[Ehi Eromosele]

how do I get matlab to realize that? I've been trying everything.

[Image Analyst]

Look up "anonymous function" in the help.