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exp(-x) - sinx = 0

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reza
reza on 10 Jan 2014
Edited: Youssef Khmou on 11 Jan 2014
hi, i'm planning to reach the root of this function:
exp(-x) - sinx = 0;
here is my code:
------------------------------
x0 = input('please enter x0 ::: ');
eps = input('please enter steps ::: ');
% eps is the step
iterator = 0;
for i=0:eps:x0
x=x+exp(-x) - sin(x);
iterator = iteratio + 1;
end
disp('root ::: '); disp(x);
disp('iterate count ::: '); disp(iterator);
------------------------------
well i can't make it work. can you help me with that?

Answers (2)

Mischa Kim
Mischa Kim on 10 Jan 2014
Try the fzero function. Unless, of course, you would like to do it on your own.

reza
reza on 10 Jan 2014
Now it's working,
x0 = input('please enter x0 ::: '); eps = input('please enter steps ::: '); iterator = 0; x=0; iterator = 0; for i=0:eps:x0 x=x+exp(-x) - sin(x); iterator = iterator + 1; end disp('root ::: '); disp(x); disp('iterate count ::: '); disp(iterator);
thanks to all.
  6 Comments
Mischa Kim
Mischa Kim on 11 Jan 2014
By solutions you mean roots? Here is the function plot:
Youssef  Khmou
Youssef Khmou on 11 Jan 2014
Edited: Youssef Khmou on 11 Jan 2014
alright, infinite number of solutions with period of ~3.1
thanks

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