Problem 1253. Infinite precision division

Solution 1596888

Submitted on 1 Aug 2018 by William

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Test Suite

Test	Status	Code Input and Output
1	Pass	dividend = '122333444455555666666777777788888888999999999'; divisor = 42; quotient_correct = '2912701058465611111113756614021164023809523'; remainder_correct = 33; [quotient,remainder]=strdiv(dividend,divisor); while and(numel(quotient)>0,quotient(1)=='0') quotient=quotient(2:end); end assert(isequal([quotient_correct ' ' num2str(remainder_correct)],[quotient ' ' num2str(remainder)]))

Test

Status

Code Input and Output

Pass

dividend = '122333444455555666666777777788888888999999999'; divisor = 42; quotient_correct = '2912701058465611111113756614021164023809523'; remainder_correct = 33; [quotient,remainder]=strdiv(dividend,divisor); while and(numel(quotient)>0,quotient(1)=='0') quotient=quotient(2:end); end assert(isequal([quotient_correct ' ' num2str(remainder_correct)],[quotient ' ' num2str(remainder)]))

Problem 1253. Infinite precision division

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Problem 1253. Infinite precision division

Test Suite

Suggested Problems

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