Solution 107816

Submitted on 8 Jul 2012 by Th B

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1 Comment

1 Comment

Cris Luengo on 14 Jul 2012

I think HIST would be more correct here than HISTC, as HIST takes bin centres as an argument, rather than bin edges.
But this is a very clever solution. I'm using min:max as bin centres, quite a bit longer!

Test Suite

Test	Status	Code Input and Output
1	Pass	%% x = [1 2 5 2 2 7 8 3 3 1 3 8 8 8]; y_correct = [2 3]; assert(isequal(threeTimes(x),y_correct))
2	Pass	%% x = [1 1 1]; y_correct = [1]; assert(isequal(threeTimes(x),y_correct))
3	Pass	%% x = [5 10 -3 10 -3 11 -3 5 5 7]; y_correct = [-3 5]; assert(isequal(threeTimes(x),y_correct))

Test

Status

Code Input and Output

Pass

%% x = [1 2 5 2 2 7 8 3 3 1 3 8 8 8]; y_correct = [2 3]; assert(isequal(threeTimes(x),y_correct))

Pass

%% x = [1 1 1]; y_correct = [1]; assert(isequal(threeTimes(x),y_correct))

Pass

%% x = [5 10 -3 10 -3 11 -3 5 5 7]; y_correct = [-3 5]; assert(isequal(threeTimes(x),y_correct))

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Problem 39. Which values occur exactly three times?

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Problem 39. Which values occur exactly three times?

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