Hello there. I ran a matlab program and i cant produce any graph. This program can run but it doesnt show any graph.. Please help me

L = 1.;
T = 1.;
maxk = 2500;
dt = T/maxk;
n=50;
dx = L/n;
cond = 1/4;
b = 2.*cond*dt/(dx*dx);
for i= 1:n+1
x(i) = (i-1)*dx;
u(i,1) = sin(pi*x(i));
end
for k=1:maxk+1
u(1,k) = 0.;
u(n+1,k)=0.;
time(k) = (k-1)*dt;
end
for k=1:maxk
for i=2:n;
u(i,k+1)=u(i,k)+0.5*b*(u(i-1,k)+u(i+1,k)-2.*u(i,k));
end
end
figure (1)
plot (x,u(:,1),'-',x,u(:,100),'-',x,u(:,300),'-',x,u(:,600),'-')
title ('Temperature within the explicit method')
xlabel ('X')
ylabel ('Y')
figure (2)
mesh (x,time,u')
title ('Temperature within the explicit method')
xlabel ('X')
ylabel ('Temperature')

[dpb]

Format the code to be legible...

[iwan]

How to make the question look legible?

[Image Analyst]

http://www.mathworks.com/matlabcentral/answers/13205-tutorial-how-to-format-your-question-with-markup. Also, before you paste your code in here, type control-a and then control-i in the MATLAB editor to fix the indenting.

Answer 1

[Image Analyst]

I copied and pasted your code and it made beautiful plots for me. Are you saying that no figure windows at all are created?

[iwan]

I need to create a table.. based on the graph. thats it..

[Image Analyst]

Info on tables: http://blogs.mathworks.com/loren/2013/09/10/introduction-to-the-new-matlab-data-types-in-r2013b/

Or you can use the uitable() function. Not sure which you want.

Answer 2

[Youssef Khmou]

Like @Image Analyst said, its working correctly, the cause may be some stored variables with same names, use clear before running the code :

 clear all,
 L=1.;
 ....

[iwan]

I need to create a table.. based on the graph. thats it..