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Is there a way to automatically extract the first and last number in a for loop?

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Mo A
Mo A on 21 Jun 2021
Edited: Mo A on 21 Jun 2021
I'm working on a loop that automatically generates nodes and their coordinates. But I've simplified the code to this so it still works:
fid = fopen('hello.txt','w')
w = 100
h = 100
x1 = 30; y1 = 5;
for i= 1 : y1
y = (i+1)/y1 * h
for j= 1 :x1
sd = i*x1 + j + 1
x = (j+1)/x1 * w
ns= ([sd,x,y,0.0])
fprintf(fid,'%10d,%10f,%10f,%10f\n', ns)
end
end
%First, Last , First
So my question is, is there a way to automatically extract the first and last number in the sd column and place them in a format like: First, Last, First. Even if the numbers assigned to the variables at the top changes?

Answers (1)

KALYAN ACHARJYA
KALYAN ACHARJYA on 21 Jun 2021
Edited: KALYAN ACHARJYA on 21 Jun 2021
So my question is, is there a way to automatically extract the first and last number in the sd column and place them-
Just store the sd as array
sd=zeros(1,length(x1));
for
for loop
sd(j)=
end
end
First Array Element
sd(1)
& Last Array Element
sd(end)
Set the format as per the requirements
%[first,last,...]
data=[sd(1),sd(end)]
  1 Comment
Mo A
Mo A on 21 Jun 2021
Hi Kalyan, thank you for your answer. I've tried running the code with the ones you've provided but its not giving me the exact values for the first and last array element.
w = 100
h = 100
x1 = 30; y1 = 5;
sd =zeros(1,length(x1));
for i= 1 : y1
y = (i+1)/y1 * h
for j= 1 :x1
sd(j) = i*x1 + j + 1
x = (sd(j)+1)/x1 * w
ns= ([sd(j),x,y,0.0])
fprintf(fid,'%10d,%10f,%10f,%10f\n', ns)
end
end
data=[sd(1),sd(end)]
I'm not sure why that is?

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