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How can i use the output of function after parfor loop?

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The following is my code
parfor ii =1:10
for jj = 1:length(DynamicAnalysis.Name)
chk=1;
GroupName=char(GlobalGroupDescrption(ii));
fprintf('Working on Extracting Frame Component Forces for %s Analysis %s\n',GroupName,DynamicAnalysis.Name{jj});
FrameComponentResults=GetFrameComponentResults(DynamicAnalysis.Name{jj},DynamicAnalysis.Number(jj),DynamicAnalysis.TimeStep(jj),DIR{jj},ii,GroupData,PerformGroup,GroupComponentType,EleComponentType,EleComponentRepeat,SortedEleCompType,SortedEleCompRepeat);
%%%%%
end
end
As outlined, GetFrameComponentResults is a function. The output of the function is FrameComponentResults, which is a struct array. How can I prevent the FrameComponentResults from being considered as a temporary variable so that I store its content following each "jj" for-loop iteration.

Accepted Answer

Walter Roberson
Walter Roberson on 19 Apr 2021
parfor ii =1:10
for jj = 1:length(DynamicAnalysis.Name)
chk=1;
GroupName=char(GlobalGroupDescrption(ii));
fprintf('Working on Extracting Frame Component Forces for %s Analysis %s\n',GroupName,DynamicAnalysis.Name{jj});
FrameComponentResultsj{jj} = GetFrameComponentResults(DynamicAnalysis.Name{jj},DynamicAnalysis.Number(jj),DynamicAnalysis.TimeStep(jj),DIR{jj},ii,GroupData,PerformGroup,GroupComponentType,EleComponentType,EleComponentRepeat,SortedEleCompType,SortedEleCompRepeat);
%%%%%
end
FrameComponentResults(ii,:) = FrameComponentResultsj;
end
  4 Comments
Walter Roberson
Walter Roberson on 20 Apr 2021
You should initialize Frame Components Results as a 2d cell array.

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More Answers (1)

Edric Ellis
Edric Ellis on 19 Apr 2021
You need to output the result into some sort of "sliced variable". Basically this means outputting an array where one of the subscripts is the parfor loop variable. For example:
parfor ii = 1:2
for jj = 1:2
% Here, 'out' is a sliced output variable.
out{ii,jj} = struct('result', ii + jj);
end
end
format compact, celldisp(out)
out{1,1} = result: 2 out{2,1} = result: 3 out{1,2} = result: 3 out{2,2} = result: 4
  2 Comments
Edric Ellis
Edric Ellis on 20 Apr 2021
Hm, you might be tripping over the rule about the bounds of the nested for loop. It might work to do this:
Ni = length(DynamicAnalysis.Name)
parfor ii = 1:10
for jj = 1:Ni
out{ii,jj} = ...
end
end

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