Logical comparison (>= to be specific) between each element (row) of a column vector, and all elements inside each row of a matrix having same number or rows, respectively
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Jonathan Morcos
on 25 Nov 2020
Commented: Jonathan Morcos
on 25 Nov 2020
I am wondering if there is a better/faster way to do this, perhaps without a for loop?
Say, I have a 30x50 matrix A, and a 30x1 column vector B. I want to procuce a 30x50 logical matrix C, where each element of C is 1 if the corresponding element of A is greater than or equal to the element of B located on the same row as that element.
For a small example:
>> A = [1 2 3 4 5 6; 7 8 9 10 11 12; 13 14 15 16 17 18];
B = [4 10 16]';
%numbers are in ascending order to simplify example
C = false(3,6);
c = 1;
for k = B'
C(c,:) = (A(c,:) >= k);
c = c + 1;
end
The output:
C
C =
3×6 logical array
0 0 0 1 1 1
0 0 0 1 1 1
0 0 0 1 1 1
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