Matrix build: Switch/Case and For loop
1 view (last 30 days)
Show older comments
I am attempting to code a 32X32 matrix and a 32X1 matrix using a switch inside of a for loop. I keep getting an error stating
"Undefined function 'eq' for input arguments of type 'cell'."
When running the below stated code. Can anyone please point to what I am doing wrong? Thank you.
A = zeros(32,32);
C = zeros(32,1);
for i = 1:32;
switch i
case i == 1
A(i,1) = -4;
A(i,2) = 1;
A(i,5) = 1;
C(i) = -600;
case i == {2,3}
A(i,i-1) = 1;
A(i,i+1) = 1;
A(i,i+4) = 1;
A(i,i) = -4;
C(i) = -300;
case i == 4
A(i,3) = 2;
A(i,4) = -4;
A(i,8) = 1;
C(i) = -300;
case i == 29
A(i,25) = 2;
A(i,29) = -6;
A(i,30) = 1;
C(i) = -500;
case i == 32
A(i,28) = 2;
A(i,31) = 2;
A(i,32) = -6;
C(i) = -200;
case i == {5,9,13,17,21,25}
A(i,i+1) = 1;
A(i,i-4) = 1;
A(i,i+4) = 1;
A(i,i) = -4;
C(i) = -300;
case i == {6,7,10,11,14,15,18,19,22,23,26,27}
A(i,i-1) = 1;
A(i,i+1) = 1;
A(i,i-4) = 1;
A(i,i+4) = 1;
A(i,i) = -4;
C(i) = 0;
case i == {8,12,16,20,24,28}
A(i,i-1) = 2;
A(i,i-4) = 1;
A(i,i+4) = 1;
A(i,i) = -4;
C(i) = 0;
case i == {30,31}
A(i,i-1) = 1;
A(i,i+1) = 1;
A(i,i-4) = 2;
A(i,i) = -6;
C(i) = -200;
end
end
0 Comments
Answers (1)
Azzi Abdelmalek
on 24 Feb 2013
Edited: Azzi Abdelmalek
on 24 Feb 2013
Just write case {2,3}
i=2
switch i
case 1
A(i,1) = -4;
A(i,2) = 1;
A(i,5) = 1;
C(i) = -600;
case {2,3}
A(i,i-1) = 1;
A(i,i+1) = 1;
A(i,i+4) = 1;
A(i,i) = -4;
C(i) = -300;
end
See Also
Categories
Find more on Matrix Indexing in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!