How to use find function to create a sceond array?

I'm trying to use find function to create a new array(Y) where the values are natural logarithms of an array (X) if these values are greater than 1. If there are any values remaining in (Y), I need to add 8 to each of the corresponding elements in A.

So far I got this but I'm pretty sure I've got something missing as I dont think I get the right result:

bold

X=[1.92 0.05 -2.43 -0.02 0.85];

Y=zeros(size(X));

log=find(log(X)>=1);

Y(1:length(log))=X(log);*

Any advice would be helpful, thank you.

[Azzi Abdelmalek]

What is the size of A

X is not used

[Patrick]

A is meant to be X, sorry for the confusion.

[Azzi Abdelmalek]

what should be the result in this case?

[Patrick]

I think it should go along these lines 0.2833 0.9057 0.7458 0.9020 0.8543

[Azzi Abdelmalek]

do you mean to add 8 or log(8)

[Azzi Abdelmalek]

it's not clear, how did you get 0.2833

[Patrick]

add 8

Answer 1

[Azzi Abdelmalek]

Don't use log as a variable, because it's a logarithme function

note that log of a negative number is complex

 log(-6)

[Azzi Abdelmalek]

X=[1.92 0.05 -2.43 -0.02 0.85];
Y=zeros(size(X));
lo =find(X>=1);
Y(1:length(lo))=log(X(lo ));

[Patrick]

Thanks, I'll try to go with this but still not sure how to add that 8 when value is less than 1.

[Azzi Abdelmalek]

then use

X=[1.92 0.05 -2.43 -0.02 0.85];
Y=8*ones(size(X));
lo =find(X>=1);
Y(1:length(lo))=log(X(lo ));