I want to repeat this code 32 times and each time stores the result to get matrix 1*32
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Osama Dwairi
on 14 May 2020
Commented: Osama Dwairi
on 14 May 2020
counter=0;
for i=1:256
for j= 1:256
if L(i,j) == k
counter= counter+1;
end
end
end
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Accepted Answer
Geoff Hayes
on 14 May 2020
Osama - presumably you want to store the counter value from each of the 32 iterations so you could do something like
n = 32;
counter = zeros(n,1);
for m = 1:n
for i=1:256
for j= 1:256
if L(i,j) == k
counter(m) = counter(m) + 1;
end
end
end
end
I'm assuming that there is some missing code since the above will produce the same result (i.e. all elements of counter will be identical) for each of the 32 iterations.
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