sum of 10-9+8+...+2-1 with results in the middle as follow. (Must use the repetition structure)

How can I solve this problem with the loop?

sum of 10-9+8+...+2-1 with results in the middle as follow.

You must use the repetition structure.

10=10

10-9=1

10-9+8=9

.

.

.

10-9+8-7+6-5+4-3+2-1=5

The calculation process should also be shown in the command window.

[Walter Roberson]

Hint: fprintf() with '%+d' format and no spaces between the elements.

[Stephen23]

Original question at 2019-11-24 01:35:57:

"sum of 10-9+8+...+2-1 with results in the middle as follow with the loop"

sum of 10-9+8+...+2-1 with results in the middle as follow by using loop

10=10

10-9=1

10-9+8=9

.

.

.

10-9+8-7+6-5+4-3+2-1=5

Answer:

Revised question at 2019-11-24 02:31:23:

How can I solve this problem with the loop?

sum of 10-9+8+...+2-1 with results in the middle as follow.

You must use the repetition structure.

10=10

10-9=1

10-9+8=9

.

.

.

10-9+8-7+6-5+4-3+2-1=5

The calculation process should also be shown in the command window.

Revised question at 2019-11-24 06:14:08:

"How can I solve this problem?"

Sum of 10-9+...+2-1

[Rena Berman]

(Answers Dev) Restored edit

Answer 1

[David Hill]

m=10;
[sprintf('%d',m),sprintf('=%d',sum(m))]
x=[];
for k=9:-1:1
    x=[x,k*(-1)^k];
    [sprintf('%d',m),sprintf('%+d',x),sprintf('=%d',10+sum(x))]
end