how many times specific number repeated in cell

E=[1  2;1  5;2  3;2  4;2  5;3  4;4  5;4  7;4  9;5  6;6  11;6  12;6  13;7  8;7  9;9  10;9  14;10  11;12  13;13  14];
N=(1:max(E(:)))'; 
A=[];
for i=1:max(E(:))
    if sum(any(ismember(E,N(i)),2),1)==2
       A(i)=N(i); 
    end
end
A(A==0)=[]; %specific number 
B={[1,2,5],[2,3,4],[1,2,4,5],[1,2,4,5,6,9,10,11],[1,2,4,5,6,9,13,14]}; % want to see how many times

for i = 1:numel(B)
    count = 0 ;
    for j = 1:numel(A)
        [c,ia] = ismember(B{i}, A(j)) ;
        if any(c)
            count = count+1 ;
            
        end
    end
    number_of_repeat{i} = count ;
 end

I want have, how many times each elamnet of A is repeated in B

I used above code but does gives me what I want

result should be:

result=[1,4;3,1;10,1;11,0;12,0;14,1] 

means that 1 is repeated 4 times. 3 is repeated 1 times.

[Stephen23]

You can generate A much more efficiently using a histogram function:

>> N = 1:max(E(:)); 
>> X = hist(E(:),N);
>> A = N(X==2)
A =
  1  3  10  11  12  14

Answer 1

[madhan ravi]

Note: You have a mistake in your desired result 11 appears once.

v=[B{:}]; % assuming each contents of B is a vector if not make them as one and then proceed
result=[A(:),sum(v==unique(A).',2)]

Gives:

result =

     1     4
     3     1
    10     1
    11     1
    12     0
    14     1