How to get an array of all field elements of a 1xN structure?

Hi. I was not able to find an answer to my question, so I am asking it here. Is there a more direct way to get an array of all elements of a structure.field?

What I want is a direct one-liner which gives me the same as:

for ii = 1:length(Results)
   Test(ii,1) = Results(ii).end_dates;
end

(Test is a 222x1 array)

something like:

Test = Results(:).end_dates

whereby this line somehow just gives me Results(1).end_dates, so just the first element of the field...

This is my structure: (a little bit small here, so also as an attachement)

[Matt]

Hi Sebastian,

You can do something like this with the commands:

Test = {Results.mid_time}

if you want the results in a cell array, or

Test = [Results.mid_time]

if you want the results in a vector.

Results.mid_time gives you a comma separated list of the elements, and the brackets {} or [] concatenate them together into an array.

I hope this helps.

Matt

[Sebastian]

Yeah thank you very much!

Continually learning new stuff =)

Answer 1

[Adam Danz]

If the values stored in .end_dates are scalars,

Test = [Results(:).end_dates]';   %Test will be column vector

If the values stored in .end_dates are row vectors of identical length,

Test = cell2mat({Results(:).end_dates}');  %Test will be matrix

If the values stored in .end_dates are column vectors of identical length,

Test = [Results(:).end_dates];   %Test will be a matrix 

If the values stored in .end_dates are strings or matricies of uneqal size,

Test = {Results(:).end_dates}';  % Test will be a columnar cell array

[Sebastian]

Thank you!

So I missed the square brackets... ^^'

[Adam Danz]

Glad I could help!