how can i create in script y=cos(x), between (0,2*pi) linspace(0,1,n) and the angel is 10degrees using for (loop) and Disp and SprintF

help :(

[madhan ravi]

what have you tried so far??

[mustafa alawneh]

%sinefun3.m n=21; x=linspace(0,1,n); %x=2*pi*linspace(0,1,n); y=sin(2*pi*x); %y=sin(x); disp('hi ') disp(' k x(k) sin(x(k))') for k=1:n degrees = (k-1)*360/(n-1); disp(sprintf('%2.0f %3.0f %6.3f ',... k ,degrees,y(k))) end disp(' ') disp(sprintf('one Degree = %5.3e Radians ',... pi/180))

this is in sine and the angle number is 18

[mustafa alawneh]

i cosine the number of N=33

[mustafa alawneh]

N is the number of angel between 0 and 2pi

[madhan ravi]

Do you realise that cosd() takes degrees as input argument?

[mustafa alawneh]

cosd??! yes i realise that but i want to say that im student and new in matlab and i need the answer As soon as

[mustafa alawneh]

do you have facebook for help me please ?

Answer 1

[mustafa alawneh]

%sinefun3.m n=21; x=linspace(0,1,n); %x=2*pi*linspace(0,1,n); y=sin(2*pi*x); %y=sin(x); disp('hi ') disp(' k x(k) sin(x(k))') for k=1:n degrees = (k-1)*360/(n-1); disp(sprintf('%2.0f %3.0f %6.3f ',... k ,degrees,y(k))) end disp(' ') disp(sprintf('one Degree = %5.3e Radians ',... pi/180))