Combination of multiple arrays

Lets have two arrays of same length, A = [2 4 6 8 10], B = [5 8 3 7 2], I want to know how to have a resultant array which will contain, result = [2 5 4 8 6 3 8 7 10 2]; If the lengths are different, suppose, A = [2 4 6 8 10], B = [5 8 3], so how will I get the result as [2 5 4 8 6 3 8 10];

Answer 1

[Birdman]

Consider A has more element than B:

A=2:2:10
B=[5 8 3]
result=zeros(1,numel(A)+numel(B));
Dif=2*numel(B);
dif=numel(A)-numel(B);
result(end:-1:Dif+1)=A(end:-1:numel(A)-dif+1);
A(end:-1:numel(A)-dif+1)=[];
result(1:2:Dif-1)=A;
result(result==0)=B

Answer 2

[Stephen23]

Faster, much simpler code, uses less memory, creates only one intermediate variable (a scalar value), and works regardless of which vector is longer. For two row vectors A and B, all you need is:

>> A = [2,4,6,8,10];
>> B = [5,8,3];
>> N = min(numel(A),numel(B));
>> C = [reshape([A(1:N);B(1:N)],1,[]),A(N+1:end),B(N+1:end)]
C =
    2    5    4    8    6    3    8   10

[Birdman]

Yup, deserved an upvote. But at least mine does not involve a loop, improvement comparing to my beginner time ;-)