loop for matlab array

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best16 programmer
best16 programmer on 23 Nov 2016
Edited: James Tursa on 23 Nov 2016
i have a problem with for loop.we have a vector a=[0 1 1 1 0] and a vector b=[1 1 1 1 1]
for i = 1:length(a)
if a(i)==0
c = [-1.*b] ;
else if a(i)==1
c = [1.* b];
end
end
the loop works only for a(1)=0 and stops.

Answers (3)

Geoff Hayes
Geoff Hayes on 23 Nov 2016
Try removing the space between the else if. Re-write this as
if a(i)==0
c = [-1.*b] ;
elseif a(i)==1
c = [1.* b];
end
  4 Comments
best16 programmer
best16 programmer on 23 Nov 2016
yes i know,i'm trying to display the result c in a edit text
Image Analyst
Image Analyst on 23 Nov 2016
Then just do
handles.edit1.String = sprintf('%d ', c);
This will convert the vector to a string and put it into the edit text box on your GUI.

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Image Analyst
Image Analyst on 23 Nov 2016
Maybe you wanted elseif instead of "else if". This works and does several iterations:
a=[0 1 1 1 0]
b=[1 1 1 1 1]
for i = 1:length(a)
if a(i)==0
c = [-1.*b]
elseif a(i)==1
c = [1.* b]
end
end
Of course there are better ways to do that and no experienced MATLAB programmer would do that operation like that.
  3 Comments
best16 programmer
best16 programmer on 23 Nov 2016
the problem is how can we display all the c values in a edit text
Image Analyst
Image Analyst on 23 Nov 2016
They will all be displayed because there is no semicolon at the end of the line. Did you actually try it and look in the command window?

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Andrei Bobrov
Andrei Bobrov on 23 Nov 2016
c = (a(:)*2 - 1)*b(:)';
or
c = (a(:)*2 - 1).*b(:);

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