calling seperate members of a vector function

I want to call seperate members of my defined vector function and I don't know how to do it.

For example I defined the vector function as shown:

F=@(x,y,z) [x- y, y^2 , z+2] which shows:

@(x, y, z) [x - y, y ^ 2, z + 2]

how do i call only one member, like the first one "x-y"? Because if I do F(1) I'm defining x as equal to 1.

[Ive J]

Why not this?

F = @(x) [x(1) - x(2), x(2)^2 , x(3) + 2];
res = F(1:3);
res(1)

ans = -1

Answer 1

[Matt J]

There's no way to do that. You could do it if the components are held in struct form, e .g.,

F=@(x,y) struct('a',x-y,'b', y^2);

F(5,3).a

ans = 2

[João Teixeira]

Ok, thanks for your help!

[Matt J]

You're welcome, but if you consider your question answered, please Accept-click the answer.