Repetition of elements in a matrix

Suppose i have a matrix A= [25 21 ] . I want to repeat elements by 4 and 2 times respectively. Repeat=[4 2]. However the repeated values will be in proportion i.e. Proportion=[8 17]. The sum of proportion repeated element will be equal to A matrix elements. It means that final matrix will be B= [8 8 8 1 17 4].

(25=8+8+8+1 , 21=17+4 )

Pls suggest code to generate matrix B

Answer 1

[Walter Roberson]

A = [25 21 ]

A = 1×2

25 21

Repeat = [4 2]

Repeat = 1×2

4 2

Proportion = [8 17]

Proportion = 1×2

8 17

leftover = A - Proportion .* (Repeat-1);
toRepeat = reshape([Proportion; leftover],1,[]);
repeatCount = reshape([Repeat-1; ones(1,length(Repeat))],1,[]);
B = repelem(toRepeat, repeatCount)

B = 1×6

8 8 8 1 17 4

[Danish Nasir]

It nearly solved my problem. I just want to add one complexity in the problem. There is a 3rd element in the matrix which i do not want to propotionate

A=[25 21 30]

Repeat=[4 2 1]

Proportion=[8 17 30].

B=[8 8 8 1 17 4 30]

Can you suggest how to generate B?

[Walter Roberson]

The code already handles that.

A = [25 21 30]

A = 1×3

25 21 30

Repeat = [4 2 1]

Repeat = 1×3

4 2 1

Proportion = [8 17 30]

Proportion = 1×3

8 17 30

leftover = A - Proportion .* (Repeat-1);
toRepeat = reshape([Proportion; leftover],1,[]);
repeatCount = reshape([Repeat-1; ones(1,length(Repeat))],1,[]);
B = repelem(toRepeat, repeatCount)

B = 1×7

8 8 8 1 17 4 30